lines ab and cd intersects at M. if the m AMD = 2+×20 and the m DMB = 3×+60degree find the measure of AMC
neela1:
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3x+60+2x+20 = 180'
5x=180-80
x=100/5=20
AMC=3x+60=120
5x=180-80
x=100/5=20
AMC=3x+60=120
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