Math, asked by anamika2819, 1 year ago

lines and angle base question

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Answered by Anonymous
0
ᴏᴋ ᴅᴜᴅᴇ
130°+y=180°
y=50°
ᴇxᴛᴇɴᴅ ᴛꜱ ꜱᴛʀᴀɪɢʜᴛ ᴛᴏ ᴍ
ᴀɴɢʟᴇ ᴏꜱᴛ+ ᴀɴɢʟᴇ ᴏꜱᴍ= 180°
85°+ ᴀɴɢʟᴇ ᴏꜱᴍ=180°
ᴀɴɢʟᴇ ᴏꜱᴍ=95°
ᴀɴɢʟᴇ ᴏꜱᴍ ᴀɴᴅ x ꜰᴏʀᴍꜱ ᴄᴏʟɪɴᴇᴀʀ ᴀɴɢʟᴇꜱ
ᴀɴɢʟᴇ ᴏꜱᴍ+ x= 180°
95°+x=180°
x=85°
x+y=85°+50°
=135°
Answered by Anonymous
10
\textbf{Heya}

\textbf{Given :-}

PQ || ST

/_ PQR = 130°

/_ TSO = 85°

/_ OQR = x

/_ QOS = y

\textbf{To find :-}

x + y = ?

\textbf{Solution :-}

/_ PQR + /_OQR = 180° (Linear pair)

130° + x = 180°

x = 180° - 130°

\textbf{x = 50°}

Now,

PQ || ST

/_ TSO = /_ SOQ (Alternate interior angles)

85° = y

\textbf{y = 85°}

Now,

x + y = 50° + 85°

\textbf{x + y = 135°}

\textbf{Hope this helps you.}
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