LINES AND ANGLES
10.15
5. In Fig. 10.35, ZAOC and ZBOC form a linear pair. If a – 2b = 30°, find a and b.
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a+b=180 (linear pair)
a=180-b
a-2b =30
180-b-2b=30
180-3b=30
180-30=3b
150=3b
50=b
b=50
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Given
angle AOC and angle BOC form a linear pair.
angle AOC =a , angle BOC=b
and a-2b=30.
Find the value of a and b .
To proof
As given
angle AOC and angle BOC form a linear pair
∠AOC + ∠BOC = 180°
put the value
a + b = 180
than the two equation becomes
a-2b=30 and a + b = 180
multiply a + b = 180 by 2 and subtracted from a-2b=30
2a + 2b - 2a + 4b = 360 - 60
6b = 300
b = 50
put this in the equation a + b = 180
a + 50 =180
a = 130
the value of a = 130 and b = 50
Hence proved
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