Question

Lines and angles class 9​

Answer 1

210°

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Answer 2

Answer:

210 Degrees

Step-by-step explanation:

∠RPQ = ∠PRC = 50 Degrees (Alternate interior angles)

∠PRC + ∠PRS = 180 Degrees (Linear Pair)

50 + y = 180     y = 180-50 = 130 degrees

So, y = 130 degrees

∠DST + ∠FTS = 180 Degrees ( Co-interior angles are supplementary)

110 + ∠FTS = 180

∠FTS = 180 - 110 = 70 Degrees

∠RTE + ∠RTS + ∠FTS = 180 Degrees (Linear pair)

30 + x + 70 = 180

100 + x = 180

x = 180 - 100 = 80 Degrees

x = 80 Degrees

y = 130 Degrees

x + y = 130 + 80

130 + 80 = 210 Degree

210 DEGREES IS THE ANSWER