Question

Lines and angles question

Answer 1

We have ,∠ABC + ∠BCA + ∠CAB = 180°=>90° + ∠BCA + ∠CAB = 180°=>∠BCA + ∠CAB = 180°=> (∠BCA + ∠CAB ) = X 90°=> (∠BCA + ∠CAB = 45°=> ∠OCA + ∠OCA = 45°=> ∠AOC + ∠OCA + ∠OCA = ∠AOC + 45° (Adding ∠AOC on both side )=> 180° = ∠AOC + 45°So, ∠AOC = 135° Ans ...