Question

lines and the x-axis.
(1) 3x-y-2=0
y = 3r-?
ttby​

Answer 1

Answer:

Given,

x−y+1=0....(1)

3x+2y−12=0....(2)

put x=0 in (1)

0−y+1=0⇒y=1

(0,1).....(a)

put y=0 in (2)

3x+2(0)−12=0→x=4

(4,0).....(b)

put x=0 in (2)

3(0)+2y−12=0→y=6

(0,6)......(c)

put y=0 in (1)

x−0+1=0⇒x=−1

(−1,0)...(d)

From figure, the vertices of triangle are (−1,0),(2,3),(4,0)

solution