Question

lines of and Rs intersect each other at point 0. if <POR= 2:4.find all the angles​

Answer 1

Answer:

In △PRT

∠PTS=∠PRT+∠RTP (As exterior angle is equal to sum of interior opposite angles )

⇒∠PTS=95

∘

+40

∘

=135

∘

Now in △SQT

∠STQ=∠SQT+∠TSQ (As exterior angle is equal to sum of interior opposite angles )

⇒135

∘

=∠SQT+75

∘

⇒∠SQT=135

∘

−75

∘

=60

∘

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