Question

lines PQ and RS intersect each other at point 0. If LPOR: LROQ is

5: 15.Then, find the angle of LS0Q.
​

Answer 1

Answer:

POR+∠ROQ=180

o

(Linear pair of angles)

But ∠POR:∠ROQ=5:7 (Given)

Therefore, ∠POR=

12

5

×180=75

o

Similarly, ∠ROQ=

12

7

×180=105

o

Now, ∠POS=∠ROQ=105

o

(Vertically opposite angles)

and ∠SOQ=∠POR=75

o

(Vertically opposite angles)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given:ratio of POR and ROQ is 5:15

On one side of line make the angle of 180 then-

5x+15x=180

20x=180

x=180/20

x=9

5x=5×9=45

15x=15×9=135

As we know vertically opposite angles are equal.

then anglePOR is equal to angle SOQ

45°=45°

hence, SOQ=45°