Lines PQ and RS intersect each other at point O. If ∠∶ ∠=2:3, find all the angles.
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∠POR+∠ROQ=180
o
(Linear pair of angles)
But ∠POR:∠ROQ=5:7 (Given)
Therefore, ∠POR=
12
5
×180=75
o
Similarly, ∠ROQ=
12
7
×180=105
o
Now, ∠POS=∠ROQ=105
o
(Vertically opposite angles)
and ∠SOQ=∠POR=75
o
(Vertically opposite angles)
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