lines x-y-z=0, ayz+bzx+cxy=0 are at right angles if
a. a=b+c
b. a=b-c
c. c=(a-b)/2 (these are option)
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Answer:a=b+c
Step-by-step explanation:
put x=l, y=m, z=n in both the equations and then solve for l,m,n.
l-m-n=0
amn+bnl+clm=0
at the last step take help of the fact that the lines are at right angle (use product of roots).
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