Question

Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a speed of 12 mph. What was his speed for the remaining distance? What was his average speed?

Answer 1

Answer:

$Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a speed of 12 mph. What was his speed for the remaining distance? What was his average speed? <pre>Speed for 2nd leg: {{{highlight_green(matrix(1,2, 6, mph))}}} Average speed: {{{2/(15/60)}}}, or {{{highlight_green(matrix(1,2, 8, mph))}}}$

Answer 2

Answer:

Step-by-step explanation:

a) time = distance/speed

For the first half of the trip, the time used was

.. (1 mi)/(12 mi/h) = (1/12) h = 5 minutes

Then the last half of the trip took 10 minutes, 1/6 hour.

.. speed = distance/time

.. = (1 mi)/(1/6 h) = 6 mi/h

The speed for the last half of the trip was 6 mph.

b) The average speed was

.. (2 mi)/(1/4 h) = 8 mi/h

Ling's average speed was 8 mph.