Question

Liquefaction of gases by Joule Thomson effect...?​

Answer 1

$\huge\tt{QUESTION}[tex]</p><p></p><p>[tex]\tt\large\rightarrow{\frac{m}{1} - \frac{m - 3}{2} = \frac{1}{1} - \frac{m - 5}{3} }$

$\tt\large\rightarrow$Find the value of m

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$\tt\large\red\rightarrow{\frac{m}{1} - \frac{m - 3}{2} = \frac{1}{1} - \frac{m - 5}{3} }[tex]</p><p></p><p>[tex]\underline\tt{by taking LCM.....}[\tex]</p><p></p><p>[tex]\tt\large\red\rightarrow{\frac{2m - m - 3}{2} = \frac{3 - m - 5}{3} }$

$\tt\large\red\rightarrow{3(2m-m-3) = 2(3-m-5)}$

$\tt\large\red\rightarrow{6m-3m-5 = 6-2m-10}$

$\tt\large\red\rightarrow{3m-9 = -2m-4}$

$\tt\large\red\rightarrow{3m+2m = -4+9}$

$\tt\large\red\rightarrow{5m = 5}$

$\tt\large\red\rightarrow{m = \frac{\cancel{5}}{\cancel{5}}}$

[tex]\tt\huge\red\rightarrow{m = 1}[tex]

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Answer 2

yeh kyaa.............