Question

Liquid A and B form an ideal solution and A has a stronger intermolecular force. If $X_{A}$ and $X'_{A}$ are the mole fraction of A in the solution and the vapour in equilibrium, then: A) $\frac{X'_{A} }{X_{A} } =1$ B) $\frac{X'_{A} }{X_{A} } \ \textgreater \ 1$ C) $\frac{X'_{A} }{X_{A} } \ \textless \ 1$ D) $X_{A}$ + $X'_{A}$ = 1

Answer 1

Answer:

C

Explanation:

Basically if a liquid has strong intermolecular forces energy required to seperate them will be higher. So the mole fraction of A in solution would be way higher than of in vapour.