Liquid ammonia is used in ice factory
for making ice from water. If water
at 20 °C is to be converted into 2 kg
ice at 0 °C, how many grams of
ammonia are to be evaporated?
(Given: The latent heat
vaporization of ammonia=341 cal/g)
of
Answers
Answered by
2
Answer:
Answer = 586 grams.
Explanation:
Heat released in converting 2kg water at 20oC to 2kg ice at 0oC
=(2000×20×1)+(2000×80)
Mass of ammonia evaporated = m gram
Heat used by ammonia = m×341
Heat loss = Heat gain
∴200000=m×341
m=586gram
Answered by
2
Answer = 586 grams.
Explanation:
Heat released in converting 2kg water at 20oC to 2kg ice at 0oC
=(2000×20×1)+(2000×80)
Mass of ammonia evaporated = m gram
Heat used by ammonia = m×341
Heat loss = Heat gain
∴200000=m×341
m=586gram
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