Science, asked by shridhar82, 6 months ago

Liquid ammonia is used in ice factory
for making ice from water. If water
at 20 °C is to be converted into 2 kg
ice at 0 °C, how many grams of
ammonia are to be evaporated?
(Given: The latent heat
vaporization of ammonia=341 cal/g)
of

Answers

Answered by sam44257
2

Answer:

Answer = 586 grams.

Explanation:

Heat released in converting 2kg water at 20oC to 2kg ice at 0oC

=(2000×20×1)+(2000×80)

Mass of ammonia evaporated = m gram

Heat used by ammonia = m×341

Heat loss = Heat gain

∴200000=m×341

m=586gram

Answered by Anonymous
2

Answer = 586 grams.

Explanation:

Heat released in converting 2kg water at 20oC to 2kg ice at 0oC

=(2000×20×1)+(2000×80)

Mass of ammonia evaporated = m gram

Heat used by ammonia = m×341

Heat loss = Heat gain

∴200000=m×341

m=586gram

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