Liquid ammonia is used in ice factory for making ice from water. if water at 20°C is to be converted into2kg ammonia are to be evaporated? ( given: the latent heat of vaporization of ammonia= 341 cal/g )
Answers
Answer:
Heat released in converting 2kg water at 20
Heat released in converting 2kg water at 20 o
Heat released in converting 2kg water at 20 o C to 2kg ice at 0
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)Mass of ammonia evaporated = m gram
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)Mass of ammonia evaporated = m gram Heat used by ammonia = m×341
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)Mass of ammonia evaporated = m gram Heat used by ammonia = m×341 Heat loss = Heat gain
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)Mass of ammonia evaporated = m gram Heat used by ammonia = m×341 Heat loss = Heat gain∴200000=m×341
Heat released in converting 2kg water at 20 o C to 2kg ice at 0 o C=(2000×20×1)+(2000×80)Mass of ammonia evaporated = m gram Heat used by ammonia = m×341 Heat loss = Heat gain∴200000=m×341m=586gram