Question

Liquid heptane burns in oxygen gas to yield carbon dioxide and water. What mass of carbon dioxide is produced when 23.0 cm3 of heptane burns completely?

Answer 1

Answer:

According to balanced equation

1 mole (100 g) of heptane gives 7 moles of CO2 (308 g).

15 ml of heptane equals to 15 x 0.6838 = 10.257 g

If 100 g heptane gives 308 g CO2

Then 10.257 g of heptane gives how much.

Accordingly:

10.257 x 308 / 100 = 31.59 g

So 15 ml of heptane should give 31.59 g CO2. This is the correct answer for the given question.

I see under comments section that this answer is wrong. I think the given answer itself is wrong. Otherwise the intended question may be different. I don't see any other answer for this question.

Answer 2

Answer:

Given density of heptane=0.6838g/mL and MW=100g/NL]

C7H16+1102---->7CO2+8H2O