liquid is filled in a vessel which is kept in a room where the room temperature is 20°C. When the temperature of the liquid is 80°C , it loses heat at the rate of 60 cal per second. What will be the rate of loss of heat when the temperature of liquid is 40°C? (a) 180 cal/s. (b) 40 (c) 30 (d) 20
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Answer:
(d) 20
Explanation:
We know that,
Q/t α (T2 – T1)
So,
[(Q/t)1]/[(Q/t)2] = [(80 – 20)]/[(40 – 20)]
[(Q/t)2] = 20 cal/s
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