Question

liquid is going in a streamline manner in a pipe one with rate of x if the same liquid is flowing in the pipe of radius half of 51 and length price the pipe one with same pressure difference the rate of flow of liquid for this type is​

Answer 1

Answer:

Thus, rate of flow of water would be halved

Explanation:

The question statement is abit having some typo errors.

We know the initial rate of flow of liquid only that it is x

So let us assume the radius is r and the length of pipe can be the height as well which we assume is h.

We apply the formula,

Area = π × r^2 × h

Now as stated ,  radius is halved and pipe length doubled;

r = r/2

And

h = 2h

Area = πr^2h

= π × (r/2)^2 ×2h

= (πr^2h)/2

Since the new area is half of initial area, the area available to water would be half in the new case.

Thus, rate of flow of water would be halved

Answer 2

Answer:Ans - 1/2^5, i.e 1/32 times

Explanation: