Question

Liquids A and B form an ideal solution and the former has stronger intermolecular forces. If XA and X'A are the mole fractions of A in the solution and vapour in equilibrium, then :

Answer 1

Answer:

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Explanation:

Answer 2

The complete question is:-

Liquids A and B form an ideal solution and the former has stronger intermolecular forces. If xₐ and x'ₐ are the mole fractions of A in the solution and vapour in equilibrium, then :

a) $\frac{x'a}{xa} = 1$

b) $\frac{x'a}{xa}>1$

c)$\frac{x'a}{xa}<1$

d)$x'a+xa=1$

Answer:

If xₐ and x'ₐ are the mole fractions of A in the solution and vapour in equilibrium, then $\frac{x'a}{xa}<1$ (Option c)

• Mole fraction and vapor pressure of a solution are directly related to each other.
• Liquid A is comparatively less volatile, therefore, partial pressure of pure liquid A is partial pressure of pure liquid B.
• Since mole fraction of a component of a solution is equal to the partial pressure of that component divided by the pressure of the entire solution. Therefore, $x'a= \frac{x'}{x'a} <1$