lir 25+3(42-5)+8(x+2) = x+3.
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- As per the data given in the question, we have to find the value of the expression.
Given data:-
To find:- value of the expression.
Solution:-
- Here, we will use the below following steps to find a solution using the transposition method:
- Step 1:- we will Identify the variables and constants in the given simple equation.
- Step 2:-then we Simplify the equation in LHS and RHS.
- Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.
- Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.
- Step 5:- Then the result will be the solution for the given linear equation.
By using the transposition method. we get,
Hence the value will be
Answered by
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x = -149/7 for 25+3(42-5)+8(x+2) = x+3
Given:
- 25+3(42-5)+8(x+2) = x+3.
To Find:
- Solve for x
Solution:
- Sequence of operation: BODMAS
- B - Bracket
- O - of
- D - Division
- M - Multiplication
- A - Addition
- S - Subtraction
Step 1:
Perform subtraction in parenthesis
25+3(42-5)+8(x+2) = x+3
=> 25+3(37)+8(x+2) = x+3
Step 2:
Remove parenthesis
25+3(42-5)+8(x+2) = x+3
=> 25+3 × 37 +8x+ 8× 2 = x+3
Step 3:
Perform multiplication:
25+3(42-5)+8(x+2) = x+3
=> 25 + 111 + 8x+ 16 = x+3
Step 4:
Add the numbers
8x + 152 = x + 3
Step 5:
Use transposition and solve for x
8x -x = 3 - 152
7x = -149
x = -149/7
x = -149/7 for 25+3(42-5)+8(x+2) = x+3
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