Lisa and paul started a journey of distance 360 km. If lisa and paul travel at the speeds of 40 kmph and 60 kmph respectively. How many minutes early can paul reach the destination?
Answers
Answered by
0
t= s/v
s= 360 km
v (lisa) = 40 km/h
time taken by lisa = 360/40= 9hr
v of paul= 60 km/h
time= 6hr
time paul will reach early= 9 -6 hr
=2hr
=120 min
s= 360 km
v (lisa) = 40 km/h
time taken by lisa = 360/40= 9hr
v of paul= 60 km/h
time= 6hr
time paul will reach early= 9 -6 hr
=2hr
=120 min
Similar questions