Question

lisa and paul started a journey of distance 360km . if lisa and pual travel at the speed of 40kmph and 60kmph respectively . how many minutes early can paul reach the destination?

Answer 1

We are given,
Distance covered = 360 km.
Speed of Lisa = 40 km/h.
Speed of Paul = 60 km/h.

Time taken by Lisa = Distance / Speed of Lisa .
=360/40.
=9 hours.

Time taken by Paul = Distance / Speed of Paul.
=360/60.
=6 hours.

9>6.

Therefore, Paul will reach the destination 3 hours earlier i.e. 3*60=180 minutes earlier.