Question

List all the 4-digit odd numbers that can be created by rearranging these number tiles
4 9 2 3
answer the THREE REMAINING LAST ONES THAT ARE ODD!!!PLZ
4923
4239
4329
9243
9423
2439
2349
3249
3429

Answer 1

Answer:

9342

3429

9234

3923

3924

Answer 2

Given:

A list of all the 4-digit odd numbers is created using the digits 4, 9, 2, 3.

To Find:

The possible list of numbers excluding the mentioned possibilities.

Solution:

The given problem can be solved by using the concepts of permutations and combinations.

1. It is given that a list of all the 4-digit odd numbers is created using the digits 4, 9, 2, 3.

2. From the given 4 digits, only 3 and 9 are odd. Hence, the number can end with either 3 or 9.

3. Hence, the total number of possibilities in the units digit is 2. There are no restrictions with the other places as the number can be odd if the last digit is odd.

4. Hence, The first place i.e thousands place has 3 possibilities as one of the numbers is already filled in the units digit. The hundredth digit has 2 possibilities as 1 digit each is filled in the units and thousandths places.

5. The tenth place has only a single possibility as all of the numbers are filled up and only 1 number is left.

6. So, the total number of possibilities will be,

=> Total number of possibilities = 3 x 2 x 1 x 2 = 12 possibilities.

• The 12 possibilities are as follows,
• 4293, 4923, 2943, 2493, 9243, 9423, 2439, 2349, 3249, 3429, 4329, 4239.