Question

List of formula of trignomentary

Answer 1

here is your answer....!!

Answer 2

Answer

$\sf{ {sin}^{ - 1}( \dfrac{1}{x}){cosec}^{ - 1} x}$

$\sf{ {cos}^{ - 1}( \dfrac{1}{x}){sec}^{ - 1} x}$

$\sf{ {tan}^{ - 1}( \dfrac{1}{x}){cot}^{ - 1} x}$

$\sf{sec}^{ - 1} \: x + {cos}^{ - 1} \: x = \dfrac{\pi}{2}$

$\sf{sec}^{ - 1} \: x + {cosec}^{ - 1} \: x = \dfrac{\pi}{2}$

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$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \tt{0}^{ \circ} & \tt{30}^{ \circ} & \tt{45}^{ \circ} & \tt{60}^{ \circ} & \tt{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered} \end{gathered}$