Question

list of the sum of 3digit natural number divisible by 4​

Answer 1

Answer:

Step-by-step explanation:

a  

n

​  

=988⇒a+(n−1)d=988⇒104+(n−1)×13=988⇒n=69

Now, Required sum =  

2

n

​  

[2a+(n−1)d]

                                 

=  

2

69

​  

[2×104+(69−1)×13]

=  

2

69

​  

[1092]

=69×546=37674