Question

List the elements in the set .
Let U = {q, r, s, t, u, v, w, x, y, z}
A = {q, s, u, w, y}
B = {q, s, y, z}
C = {v, w, x, y, z}

61) C' U 1 A'
62) C' n A'

Answer 1

Answer:

We will find the value of C' ∪ A' and C' ∩ A'  using the set value of U,A,B and C. The final Answer is C' ∪ A'  $=\left \{q,r,s,t,u,v,x,z\right\}$, C' ∩ A' $=\left \{ r,t\right\}$

Step-by-step explanation:

This question is set concept. First we should find C' and A'.

he set of elements in U that are not in A.

C' means that the set of elements in U but not in set C

That is,  $U=\left \{q, r, s, t, u, v, w, x, y, z}\right\}$

             $C=\left \{v, w, x, y, z}\right\}$

From the above two sets, we should take the elements from set U which elements should not in set C.

        ∴  $C'=\left \{q,r,s,t,u\right\}$

Similarly we do the same process for A'. A' means that the set of elements in U but not in set A.

That is,  $U=\left \{q, r, s, t, u, v, w, x, y, z}\right\}$

             $A=\left \{q, s, u, w, y}\right\}$

From the above two sets, we should take the elements from set U which elements should not in set A.

         ∴ $A'=\left \{r,t,v,x,z\right\}$

Next we can find C' ∪ A'  and C' ∩ A'.

∪ means that union of set. The union of two sets is a set containing all elements that are in A or in B.

So we should combine the elements in both C' and A' set.

That is, $C'$ ∪ $A'$ $=\left \{ q,r,s,t,u,v,x,z \right\}$

∩ means that intersection of set. The intersection of two sets is a set containing the common elements that are in A and B.

So we should write the common elements in both C' and A' set.

That is, $C'$ ∩ $A'$ $=\left \{ r,t\right\}$

Final Answer is  $C'$ ∪ $A'$ $=\left \{ q,r,s,t,u,v,x,z \right\}$

                           $C'$ ∩ $A'$  $=\left \{ r,t \right\}$