List the elements of the following set.
A= { x : x ԑ Z and x2 ≤ 4 }
What is the cardinality of the set A
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0
Answer:
the set of elements are2,3,4
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Given : A= { x : x ԑ Z and x² ≤ 4 }
To Find : List the elements of the following set.
cardinality of the set A
Solution:
A= { x : x ԑ Z and x² ≤ 4 }
x² ≤ 4
=> x ≤ | 2 |
=> -2 ≤ x ≤ 2
Hence = A = { - 2 , - 1 , 0 , 1 , 2 }
5 elements in set
n(A) = 5
cardinality of the set A = n(A) = 5
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