Question

list the uses of speed -time graph of a body​

Answer 1

Answer:

Given that,

There is a point B on the x−axis on which rays reflects

A ray passing through A(1,2) reflects on point B.

On reflection the ray passes through point C(5,3)

We need to find equation of line AB.

Since

the point B is on the x−axis

its y=0

Let the coordinates of point B(k,0)

Let the angle ∠CBX=θ

PB be the normal

∠PBX=90

o

∠XBC+∠CBP=90

o

θ+∠CBP=90

o

∠CBP=90

o

Also, ∠ABP=∠CBP=90

o

=θ

Now, ∠ABX=∠ABP+∠PBC+∠CBX

=(90

o

−θ)+(90

o

−θ)+θ

=180

o

−20+Q

∠ABX=180

o

−θ

Now, we find slope of line AB and CB

We know that

Slope of line

m=

x

2

−x

1

y

2

−y

1

m=x

2

−x

1

y

2

−y

1

Line