List three conclusion of experiment performed by Rutherford for his model of an atom
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1)Most of the space inside the atom is empty because most of the alfa–particles passed through the gold foil without getting deflected.
2)Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
3)A very small fraction of alfa–particles were deflected by 180 degree ,indicating that all the positive charge and mass of gold atom were concentrated in a very small volume within the atom.
2)Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
3)A very small fraction of alfa–particles were deflected by 180 degree ,indicating that all the positive charge and mass of gold atom were concentrated in a very small volume within the atom.
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HERE IS YOUR ANSWER.
1. he took a thin sheet of gold foil, and passed doubly charges helium particles known as alpha particles through them.
2. he proposed that at the centre of an atom resides the nucleus.
3. he even proposed that most of the space in an atom is vacant and atom is positively charged due to the prescence of nucleus.
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1. he took a thin sheet of gold foil, and passed doubly charges helium particles known as alpha particles through them.
2. he proposed that at the centre of an atom resides the nucleus.
3. he even proposed that most of the space in an atom is vacant and atom is positively charged due to the prescence of nucleus.
HOPE IT HELPS YOU! ! ! ! !
ALSO FOLLOW ME
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