listen carefully (√3 = 1.732)
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we know, the height of tree, = 12m
let the height of tree from the bottom broken by wind be 'x'm.(horizontal)
Thus,
height of tree(from borken part to top)=(12–x)m
Angle of elevation=60°
√3=1.732
To find- value of x.
In the ∆ formed respectively,
as, sin∅=opp.side/hypotenuse
sin60°=(x)÷(12–x)
√3/2=(x)÷(12–x)
12√3–√3x=2x
2x+√3x=12√3
x(2+√3)=12√3
x=(12√3)/(2+√3)
x=24√3–36 (on rationalising the denominator)
x=41.568–36 (as, √3=1.732)
x=5.567m
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pratik wo ans h
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