Math, asked by Sarim666, 6 months ago

Listen if you will solve my question properly I will mark you as brainliest and will give you 10 thanks...plz don't spam otherwise you will lose the opportunity to get 10 thanks​.​

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Answered by BʀᴀɪɴʟʏAʙCᴅ
1

\huge{\orange{\boxed{\fcolorbox{lime}{aqua}{\pink{ANSWER}}}}} \\

 log \: \frac{ {a}^{3}  {b}^{3} }{ {c}^{4} }  +  log \: \frac{b {c}^{3} }{ {a}^{2} }   -  log \: \frac{a}{c}  \\  \\  =  >  log {a}^{3} {b}^{2}  -  log {c}^{4}   +  log \: b {c}^{3}   -  log {a}^{2}  - ( log \: a  -  log \: c) \:   \\  \\  =  >  log {a}^{3}  +  log {b}^{2}   -  log \: {c}^{4}  +  log \: b \:  +  log {c}^{3}  -  log {a}^{2}  -  log \: a \:  +  log \: c \:  \\  \\  =  >  log {a}^{3}   +  log {b}^{2}   +  log \: b \:  -  log {c}^{4}  +  log {c}^{3}  +  log \: c \:  -  log {a}^{2}    -  log \: a \\  \\  =  >  log {a}^{3}   +  log {b}^{3}   -   log {c}^{4}  +  log {c}^{4}  -  log {a}^{3}    \\

 \implies \red  {log \:{b}^{3}}

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Answered by Anonymous
0

Answer:

ANSWER

\begin{gathered} log \: \frac{ {a}^{3} {b}^{3} }{ {c}^{4} } + log \: \frac{b {c}^{3} }{ {a}^{2} } - log \: \frac{a}{c} \\ \\ = > log {a}^{3} {b}^{2} - log {c}^{4} + log \: b {c}^{3} - log {a}^{2} - ( log \: a - log \: c) \: \\ \\ = > log {a}^{3} + log {b}^{2} - log \: {c}^{4} + log \: b \: + log {c}^{3} - log {a}^{2} - log \: a \: + log \: c \: \\ \\ = > log {a}^{3} + log {b}^{2} + log \: b \: - log {c}^{4} + log {c}^{3} + log \: c \: - log {a}^{2} - log \: a \\ \\ = > log {a}^{3} + log {b}^{3} - log {c}^{4} + log {c}^{4} - log {a}^{3} \\ \end{gathered}

log

c

4

a

3

b

3

+log

a

2

bc

3

−log

c

a

=>loga

3

b

2

−logc

4

+logbc

3

−loga

2

−(loga−logc)

=>loga

3

+logb

2

−logc

4

+logb+logc

3

−loga

2

−loga+logc

=>loga

3

+logb

2

+logb−logc

4

+logc

3

+logc−loga

2

−loga

=>loga

3

+logb

3

−logc

4

+logc

4

−loga

3

Step-by-step explanation:

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