Math, asked by panda806927, 11 months ago

LISTEN!!solve it plz​

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Answered by Anonymous
1

Question \:  \: Number \:  \: 08 \\  \\ x {}^{3}  -  \frac{1}{x {}^{3} }  = 14 \:  \:  \:  \: \:  \:  \:  \:  \:  \: find \:  \:  \: x -  \frac{1}{x}  \\  \\ Answer \:  \\  \\ let \:  \:  \: x -  \frac{1}{x}  = z \\  \\ cubing \: on \: both \: sides \: we \: have \\  \\ (x -  \frac{1}{x} ) {}^{3}  = z {}^{3}  \\  \\ x {}^{3}  -  \frac{1}{x {}^{3} }  - 3(x -  \frac{1}{x} ) = z {}^{3}  \\  \\ 14 - 3z = z {}^{3}  \\  \\ z {}^{3}   +  3z - 14 = 0 \\  \\ (z - 2)(z {}^{2}  + 2z  + 7) = 0 \\  \\ (z - 2) = 0 \:  \:  \:  \:  \:  \: or \:  \:  \:  \:  \:  \: z {}^{2}  + 2z + 7 = 0 \\  \\ z  =  \frac{ - 2 +  \sqrt{4 - 28} }{2}  \:  \:  \: or \:  \:  \: z =  \frac{ - 2 -  \sqrt{4 - 28} }{2}  \\  \\ z =   \frac{ - 2 +  \sqrt{ - 24} }{2}  \:  \:  \: or \:  \:  \:  z =  \frac{ - 2  -  \sqrt{ - 24} }{2}  \\  \\  \\ therefore \:  \:  \:  \:  \:  \\  \\ x -  \frac{1}{x}  = 2 \:  \:  \:  \: or \:  \:  \: x -  \frac{1}{x}  =  \frac{ - 2 +  \sqrt{ - 24} }{2}  \\  \\ or \\  \\ x -  \frac{1}{x}  =  \frac{ - 2 -  \sqrt{ - 24} }{2}


panda806927: wrong
Anonymous: Really?
panda806927: hmm
Anonymous: Then what's the Right Answer?
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