Question

Lithium aluminium hydride react with silicon tetrachloride products are

Answer 1

Hey Dear here is your Answer =)

~SiCl4 + LiAlH4 = SiH4 + LiCl + AlCl3
     (Reactants)      (Products Formed)

~ Hope it helps You Out (^_^)
~ Thanks (^^)

Answer 2

Explanation:

Lithium aluminium hydride is a reducing agent and it reduces silicon tetrachloride. As a result, products obtained are silicon hydride, lithium chloride, and aluminium chloride.

When lithium aluminium hydride reacts with silicon tetrachloride then the reaction that takes place is as follows.

     $LiAlH_{4} + SiCl_{4} \rightarrow SiH_{4} + LiCl + AlCl_{3}$