Lithium hydroxide is a carbon dioxide absorber used on the International Space Station. If 48 kg of lithium hydroxide was completely used up, what volume of liquid water could be recycled for the astronauts to drink? Use the information below to calculate your answer in cm3. The density of water is 1.0 g/cm3.
Answers
Answer:
Explanation:
About 921 grams of carbon dioxide will react woth 1.00 kg of lithium hydroxide.
Explanation:
Start with the equation for the reaction:
2
LiOH
+
CO
2
→
Li
2
CO
3
+
H
2
O
So one mole of lithium hydroxide reacts with one-half mole of carbon dioxide.
By adding up atomic masses we find that one mole of lithium hydroxide weighs about
23.9
grams and one mole of carbon dioxidecweighs about
44.0
grams.
So the ratio of lithium hydroxide to the carbon dioxide it reacts with is
23.9
grams of lithium hydroxide to
22.0
grams of carbon dioxide. Then
1.00
kg
=
1.00
×
10
3
grams of lithium will react with:
1.00
×
10
3
g LiOH
×
22.0
g CO
2
23.9
g LiOH
=
9.21
×
10
2
g CO
2
Given - Mass of lithium hydroxide : 48 kg
Density of water : 1 g/cm³
Find - Volume of water recycled
Solution - The reaction between lithium hydroxide and carbon dioxide produces lithium carbonate and water. Chemical reaction is given below - 2LiOH + CO2 --> Li2CO3 + H2O.
Here, in the reaction, 2 moles of lithium hydroxide releases 1 mole of water. 1 mole of lithium hydroxide has mass 23.95 gram and 1 mole of water has mass 18 gram.
So, 2 moles which is 47.9 gram or 48 gram of lithium hydroxide produces 18 gram of water.
Thus, 48 kilogram or 48,000 grams will produce water = 18/48*48000
Water produced = 18000 grams
Now, calculating volume of this mass of water.
Density = mass /volume
1 = 18000/volume
Volume = 18000 cm³.
Hence, volume of liquid water will be 18000 cm³.