Question

Little Gayle lifts her 40-kg body a distance of 0.25 meters in 2 seconds, Find the force she exerts, work done, and the power she delivered

Answer 1

Force exterted by Gayle on the ground

F = mg = 40(9.8) = 392 N

Workdone

W = mgh

W = 392(0.25)

W = 98 J

Power

P = W/t

P = 98/2

P = 49 W