Question

Little Kunju was in a dilemma. His Dog Bruno had recently delivered 6 puppies. They had been

named as Rocket, Tuffy, Gypsy, Chilli, Steffi and Daffy. The Puppies had to be placed in 2 cages with each

cage having exactly 3 puppies.

1. If Daffy is in cage 1, Gypsy and Chilli will not be together.

2. If Rocket is in cage 2, Chilli will be in cage 1.

3. Steffi cannot be in the same cage as Tuffy.

4. If Rocket is in cage 1, Tuffy will also be in cage 1.

Q1 : If Rocket is in cage 1, which of the following is definitely false?

a. Steffi is in cage 2.

b. Gypsy is in cage 1.

c. Daffy is in cage 2.

d. Daffy is in cage 1.

Q2 : If Daffy is in cage 1, how many different arrangements are possible?

a. 1 b. 2 c. 3 d. 4​

Answer 1

The answers to the given questions are as follows:

1. If Rocket is in cage 1, option d-Daffy is in cage 1 is definitely false.

If Rocket is in cage 1, Tuffy will also be in the same cage( according to condition 4). Only one more puppy can be kept in this cage. Possible options are Chilli, Deffy, Gypsy and Steffi.

• Tuffy and Steffi cannot be in the same cage so this option gets eliminated.
• Chilli is also eliminated as if it is kept in cage 1, Rocket has to be kept in cage 2.
• Daffy, if kept in cage 1 then Gypsy and Chilli will be together in cage 2 which is not possible.
• Therefore, the only option left is Gypsy. So all the given options are correct except option (d).
• So, in cage 1- Rocket, Tuffy and Gypsy, cage 2- Steffi, Daffy, Chilli.

2. If Daffy is in cage 1, the number of different arrangements possible are 4( option d).

The possible arrangements are-

a) Cage 1- Daffy, Chilli, Steffi

Cage 2- Gypsy, Rocket, Tuffy

b) Cage 1- Daffy, Chilli, Tuffy

Cage 2- Gypsy, Rocket, Steffi

c) Cage 1- Daffy, Gypsy, Tuffy

Cage 2- Steffi, Rocket, Chilli

d) Cage 1- Daffy, Gypsy, Steffi

Cage 2- Rocket, Tuffy, Chilli

Answer 2

Answer:

steffi cannot be in the same cage as tuffy.