Question

Little monkey had 60 peaches.
On the first day, he decided to keep 3/4 of his peaches. He gave the rest away. Then he ate one. On the second day he decided to keep 7/11 of his peaches. He gave the rest away. Then he ate one. On the third day he decided to keep 5/9 of his peaches. He gave the rest away. Then he ate one. On the fourth day he decided to keep 2/7 of his peaches. He gave the rest away. Then he ate one. On the fifth day he decided to keep 2/3 of his peaches. He gave the rest away. Then he ate one.
How many did he have left at the end?

Answer 1

Answer:

he is left with 1 apple at the end.

Step-by-step explanation:

1st day- kept 45, gave 15, ate 1, total left 44

2nd day- kept 28, gave 16, ate 1, total left 27

3rd day- kept 15, gave 12, ate 1, total left 14

4th day- kept 4, gave 10, ate 1, total left 3

5th day- kept 2, gave 1, ate 1, total left 1

final answer = 1

Answer 2

Answer:

the monkey had 1 peach at the end of fifth day

explanation in the attached image