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In the triangle ABC, if AC = BC, LA = 750 ; find angle(B )and angle (C) .
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Answer:
Solution.
let the ∆C=x
∆A=750
∆A+∆C=180°
750+x=180
x=180-750
x=570
angle C=57
let angle B=y
angle A=750
angleC=570
∆A+∆C+∆B=180°
750+570+y=180
1320+y=180
y=180-1320
y=1140
∆B=1140
angleC=570°
angleB=1140°
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