Question

LL
A presbyopic patient has near point as 30 cm
and far point as 40 cm. The dioptric power for
the corrective lens for seeing near object is​

Answer 1

Explanation:

far point (f)=-40

power of lens=reciprocal of its focal length

p=1/f

according to the formula e,

p=1/-40=-2.5D

so the answer is -2.5D