Physics, asked by guptasneha861, 5 months ago

Llicse numericals.
A solid weighs 80 gf in air and 60 gf when completely immersed in water. Calculate a. upthrustin
solid c. relative density of the solid d. density of the solid in Sl unit.
2.​

Answers

Answered by waizkazi14
0

Answer:

Solution

verified

Verified by Toppr

Correct option is

B

8

The solid apparently weighs less in water when compared to air because of the upward buoyant force acting on it when it is submerged in water.

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the fluid displaced by it.

Therefore, the apparent decrease in the weight of an object is equal to the weight of the fluid displaced by it.

Weight of displaced water = Apparent decrease in weight = 120−105=15 gf

Mass of displaced water = 15g

Volume of solid = volume of water displaced =

density

mass

=

1g/cm

3

15g

=15cm

3

Actual weight of solid = weight of solid in air =120gf (since buoyant force due to air is negligible)

Mass of solid = 120g

Density of solid =

Volume

Mass

=

15

120

=8g/cm

3

Relative density of solid =

Density

water

Density

solid

=

1g/cm

3

8g/cm

3

=8

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