Question

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¶The boiling point of water is 1008°C under normal atmospheric pressure. Convert this temperature in SI unit.

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Answer 1

S.I unit of Temperature = Kelvin

Boiling point of water, = 100.8 C° { typo mistake in yo question }

We know,

273.15 Kelvin = 1 C°

So,

Temperature in S.I unit = 100.8 + 273.15

==> 373.95 Kelvin

Answer 2

Answer:

1 degree Celsius is 273 kelvin

so 100.8 degree Celsius is 100.8+273 = 373.8kelvin

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