Question

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Provide Remainder theorem.

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Answer 1

Answer:

REMAINDER THEOREM

Let f(x) be any polynomial with degree greater than or equal to 1.

Further suppose that when f(x) is divided by a linear polynomial p(x) = (x-a), the quotient is q(x) and the remainder is r(x).

In other words , f(x) and p(x) are two polynomials such that the degree of f(x) degree of p(x) and p(x) O then we can find polynomials q(x) and r(x) such that, where r(x) = 0 or degree of r(x) < degree of g(x).

By division algorithm

f(x) = p(x).q(x) + r(x)

. f(x) = (x-a). q(x) + r(x) [ here p(x) = x-a]

Since degree of p(x) = (x-a) is 1 and degree of r(x) < degree of (x-a)

: Degree of r(x) = 0

This implies that r(x) is a constant, say k

So, for every real value of x, r(x) = k.

Therefore f(x) = (x-a). q(x) + k

If x= a,

then f(a) = (a-a). q(a) + k 0+ k = k

Hence the remainder when f(x) is divided by the linear polynomial (x-a) is f(a).

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Answer 2

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