Math, asked by nikitakale464, 16 hours ago

∆LMN ~ ∆PQR and 9×A (∆LMN). then find LM : PQ​

Answers

Answered by RvChaudharY50
1

Given :- ∆LMN ~ ∆PQR and 9 x A (APQR) = 16 XA

(ALMN).

To Find :-

  • LM: PQ = ?

Answer :-

we know that,

  • Ratio of areas of two similar ∆'s = Ratio of square of their corresponding sides .

so,

→ 9 * A (∆PQR) = 16 * A (∆LMN).

→ A(∆LMN) / A(∆PQR) = 9/16

→ LM² / PQ² = 9 / 16

→ (LM/PQ)² = (3²/4²)

→ (LM/PQ)² = (3/4)²

→ (LM/PQ) = 3/4

→ LM : PQ = 3 : 4 (Ans.)

Learn more :-

in triangle ABC seg DE parallel side BC. If 2 area of triangle ADE = area of quadrilateral DBCE find AB : AD show that B...

brainly.in/question/15942930

2) In ∆ABC seg MN || side AC, seg MN divides ∆ABC into two parts of equal area. Determine the value of AM / AB

brainly.in/question/37634605

Similar questions