Question

ln(1-2v) = -2t solve it​

Answer 1

Answer:

∫ (1+v)/(1–2v-v²)dv

Let, 1–2v-v² = z

(-2 -2v )dv = dz

or, -2(1+v)dv = dz

∫ (-1/2)dz/z = (-1/2) ln|z| + c

= (-1/2)ln| 1–2v-v²| +c [C is integral constant]