Question

ln 1÷(5cosx−12sinx)dx
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Answer 1

Answer: step:- 5cosx-12sinx=13 {5/13cosx-12/13sinx}=13 {cos@cosx-sin@ sinx}=13cos(x-@)

where sin@=12/13

cos@=5/13

@=tan^-1 (12/5)

step 2:- integrate 1/cos(x-@) dx

integrate sec (x-@) dx

now use

secx.dx =ln(secx+tanx)+c

i.e sec (x-@) dx=ln{sec (x-@)+tan (x-@)}

Step-by-step explanation:

Answer 2

Answer:

1÷(5cosx−12sinx)dx