Question

ln a 3digit number, the units digit is twice the tens digit and Hundreds digit is thrice the tens digit and the sum of digit is 18 .find the number​

Answer 1

PLEASE MARK IT AS BRAINLIEST

AND ,

Follow me

Answer:

963

Step-by-step explanation:

Let ten's place digit be x

Unit place digit = 2*x

Hundredth place digit = 3*x

Sum of all digits = 18

Ten's place digit + unit place digit + hundredth place digit = 18

x + 2x + 3x = 18

6x = 18

x = 18/6

x = 3

So,

Ten's place digit = x

= 3

Units place digit = 2x

= 2*3

= 6

Hundredth place digit = 3x

= 3*3

= 9

Therefore the no. is 963

Answer 2

Please see the attachment or you can also see below the solution.

$❥{\underline{\boxed{\large{\rm{♕Solution♕}}}}}$

$\sf{Let\:the\:tens\:digit\:be\:x}$

$\sf{Then,\: hundreds=2x}$

$\sf{And\:units\:digit=3x}$

$\sf{ATQ,}$$\sf{2x+x+3x=18}$

$\sf{6x=18}$

$\sf{x=3}$

So, tens digit =3

Hundreds Digit=6

Units digit = 9

So, required number= 639