Question

ln a rhombus P Q RS, the diagonals PR and Qs are 8 cm and 6
respectively. The length of the side of Rhombus is.​

Answer 1

Answer:

Step-by-step explanation:

here length of diagonals are given as 8 cm,6cm

let us name the point where the diagonals meet  o

os=oq=8/2=4cm

po=ro=6/2=3cm

H²=S²+S²

H²=4²+3²

H²=16+9

H²=25

H=√25

H=5CM

SO SIDE OF RHOMBUS =5CM

(AS ALL SIDES ARE EQUAL IN RHOMBUS)

Answer 2

let the PQR IS right angled triangle

Step-by-step explanation:

8*8 = 6*6 + PQ * PQ

64 = 36 + PQ^2

64-36= PQ^2

√28 = PQ

PQ = √4*√7

PQ= 2√7