Question

ln a triangle ABC, a straight line parallel to BC intersects AB and AC at point D and E respectively. If the area of ADE is one-fifth of the area of ABC and BC= 10 cm. then DE equals :

Answer 1

Answer:

Area of tringle ADE 1/5th of abc then BC=10cm &DE=5cm as DE=BC/2then. Area of tringle ADE/Area Of tringle ABC=DE squre/BC squre. 5*5/10*10=. 25/100==1/4Answer