Question

ln a triangle ABC, proof that...​

Answer 1

Answer:

in a triangle A+B+C = 180°

tan((B+C)/2)

=tan((180-A)/2)

=tan(90-A/2)

tan(90-x)=cot(x)

=cot(A/2) proved

Answer 2

Step-by-step explanation:

We know that for a traingle ABC

∠A+∠B+∠C=180

0

∠B+∠C=180

0

−∠A

2

∠B+∠C

=90

0

−

2

∠A

tan(

2

B+C

)=tan(90

0

−

2

A

)

=cot(

2

A

)