Question

ln a two digit number the unit digit is twice the tens digit and the difference between the number and the number formed by reversing the digit is 18. find the original number.​

Answer 1

Step-by-step explanation:

Let the tens digit be y.

Unit digit = 2y

Original Number=10y+2y=12y

Reversed number = (10*2y)+y=21y

21y-12y=18

9y=18

$y = \frac{18}{9}$

y=2

Original number=20+4=24

Answer 2

Answer:

24

Step-by-step explanation:

In a two digit number, the number in unit's place is twice the number in tens place.

So, let the number in ten's place be x.

Therefore, according to the given condition , the number in the unit's place be 2x.

Then, the original number would be 10x + 2x = 12x [ the number in tens place will be multiplied with 10, and number in unit's place will be multiplied with 1].

Now, according to the condition , after reversing 12x we get 21x. So,

21x -12x = 18

9x = 18

x= 18/9

x= 2

Hence the number in ten's place is 2 and the number in unit's place is 2×2=4.

Therefore the number is 24.